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vedic mathematics

every time you wonder how somebody solve arithematics so quickly, many people say its due to vedic mathematics but according to me......with the help of simple mathematics tricks you can make your own tricks......

                              multiplying numbers around 50

any number around 50 can be represented as   (50+x), suppose i want to write 47 then x=-3; and suppose i need to write 52 then x=2 so 50+2=52.
AIM: we need to find shortcut to multiply any number around 50. suppose we have two numbers around 50, they are (50+x) and (50+y), and their multiplication is M=(50+x)*(50+y).
expending M we get, M=[2500+50y+50x+xy]
or M=[100(25)+10{5(x+y)}+xy] , now from concept of number system we know that any 4 digit number example 6783 can be written as 67*100+8*10+3=6783, so we observe that 100 says that whatever coefficient it is associated with  is located at 100th place, simmilarly 10 says its is located at tenth place. 
conclusion :
M=100*25+[10{5(x+y)}]+xy...............................................................A
explaining  with example 1:
 suppose we need to find 52*51 here x=2 y=1
so at unit place we write 'x*y' that is 2*1=2 form equation A
at tenth place we write 5(x+y)=5*(2+1)=15. since we can place only one digit at tenth place so we put 5 at tenth place and carry 1.
at 100th place we write 25 and add the carried 1 and got 25+1=26.
so, M=26,52
example 2:
we need to multiply 52*54, now we have x=2 and y=4
unit digit=8, 
tenth digit=5(4+2)=30 so tenth digit is 0 and 3 is carried, 
100th digit = 25+3=28
so,M=2808.
simillarly you can design for other numbers...........with this you will need only 5 second to calculate...try to understand this.

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